1.5=4.9x^2+25x

Solution for 1.5=4.9x^2+25x equation:

1.5=4.9x^2+25x

We move all terms to the left:

1.5-(4.9x^2+25x)=0

We get rid of parentheses

-4.9x^2-25x+1.5=0

a = -4.9; b = -25; c = +1.5;
Δ = b2-4ac
Δ = -252-4·(-4.9)·1.5
Δ = 654.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{654.4}}{2*-4.9}=\frac{25-\sqrt{654.4}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{654.4}}{2*-4.9}=\frac{25+\sqrt{654.4}}{-9.8}
$